6b^2-10b=16

Solution for 6b^2-10b=16 equation:

6b^2-10b=16

We move all terms to the left:

6b^2-10b-(16)=0

a = 6; b = -10; c = -16;
Δ = b2-4ac
Δ = -102-4·6·(-16)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-22}{2*6}=\frac{-12}{12}
=-1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+22}{2*6}=\frac{32}{12}
=2+2/3
$